6p^2=-p+2

Solution for 6p^2=-p+2 equation:

6p^2=-p+2

We move all terms to the left:

6p^2-(-p+2)=0

We add all the numbers together, and all the variables

6p^2-(-1p+2)=0

We get rid of parentheses

6p^2+1p-2=0

We add all the numbers together, and all the variables

6p^2+p-2=0

a = 6; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·6·(-2)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-7}{2*6}=\frac{-8}{12}
=-2/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+7}{2*6}=\frac{6}{12}
=1/2
$